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Error on reusing table name of volatile container. #33

@osoken

Description

@osoken

The following works:

>>> l = List[str](connection=conn, table_name="somename", persist=False)
>>> del l
>>> l = List[str](connection=conn, table_name="somename")
>>> l.append("a")

while the following doesn't:

>>> l = List[str](connection=conn, table_name="somename", persist=False)
>>> l = List[str](connection=conn, table_name="somename")
>>> l.append("a")
Traceback (most recent call last):
  ...
sqlite3.OperationalError: no such table: somename

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