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Description
Groupby with pd.Series.mode throws error, if by values starts with a value from previous row.
df2 = pd.DataFrame({
"Name" : ['Thomas', 'Thomas', 'Thomas John'],
"Credit" : [1200, 1300, 900],
"Mood" : ['sad', 'happy', 'happy']
})
aggrFDColumnDetails = {
'Mood':pd.Series.mode,
'Credit':'sum'
}
df2.groupby(['Name']).agg(aggrFDColumnDetails)Problem description
When I execute the above code I got error
Exception: Must produce aggregated value
.....
....
and a lot of stack traces..
If I change the third name to John instead of Thomas John, it works as expected. ie The following code works.
df2 = pd.DataFrame({
"Name" : ['Thomas', 'Thomas', 'John'],
"Credit" : [1200, 1300, 900],
"Mood" : ['sad', 'happy', 'happy']
})
aggrFDColumnDetails = {
'Mood':pd.Series.mode,
'Credit':'sum'
}
df2.groupby(['Name']).agg(aggrFDColumnDetails)Note: We receive a lot of issues on our GitHub tracker, so it is very possible that your issue has been posted before. Please check first before submitting so that we do not have to handle and close duplicates!
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If the issue has not been resolved there, go ahead and file it in the issue tracker.
Expected Output
Groupby should work, even if first letters of column values are same
Output of pd.show_versions()
Details
[paste the output of pd.show_versions() here below this line]
INSTALLED VERSIONS
commit: None
python: 2.7.16.final.0
python-bits: 64
OS: Darwin
OS-release: 19.0.0
machine: x86_64
processor: i386
byteorder: little
LC_ALL: None
LANG: en_US.UTF-8
LOCALE: None.None
pandas: 0.23.3
pytest: None
pip: 10.0.1
setuptools: 40.0.0
Cython: None
numpy: 1.14.5
scipy: 0.13.0b1
pyarrow: None
xarray: None
IPython: 5.7.0
sphinx: None
patsy: None
dateutil: 2.7.3
pytz: 2018.5
blosc: None
bottleneck: None
tables: None
numexpr: None
feather: None
matplotlib: 2.2.2
openpyxl: None
xlrd: 1.1.0
xlwt: None
xlsxwriter: None
lxml: None
bs4: None
html5lib: 1.0.1
sqlalchemy: None
pymysql: None
psycopg2: None
jinja2: 2.10
s3fs: None
fastparquet: None
pandas_gbq: None
pandas_datareader: None