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perms-problem

Count the number of permutations that have a specific number of inversions. Given a permutation a1, a2, a3,..., an of the n integers 1, 2, 3, ..., n, an inversion is a pair (ai, aj) where i < j and ai > aj. The number of inversions in a permutation gives an indication on how "unsorted" a permutation is. If we wish to analyze the average running time of a sorting algorithm, it is often useful to know how many permutations of n objects will have a certain number of inversions.

In this problem you are asked to compute the number of permutations of n values that have exactly k inversions.

For example, if n = 3, there are 6 permutations with the indicated inversions as follows: 123 0 inversions 132 1 inversion (3 > 2) 213 1 inversion (2 > 1) 231 2inversions(2>1,3>1) 312 2inversions(3>1,3>2) 321 3inversions(3>2,3>1,2>1)

Therefore, for the permutations of 3 things -1 of them has 0 inversions

  • 2 of them have 1 inversion
  • 2 of them have 2 inversions
  • 1 of them has 3 inversions
  • 0 of them have 4 inversions
  • 0 of them have 5 inversions
  • Etc.

Input The input consists one or more problems. The input for each problem is specified on a single line, giving the integer n (1 <= n <= 18) and a non-negative integer k (0 <= k <= 200). The end of input is specified by a line with n = k = 0.

Output For each problem, output the number of permutations of {1, ..., n}with exactly k inversions.

Sample Input 30 31 32 33 42 4 10 13 23 18 80 00

Sample Output 1 2 2 1 5 0 46936280 184348859235088

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Count the number of permutations that have a specific number of inversions.

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