Optimise LiteralType.__eq__ and __hash__#20423
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| if self._hash == -1: | ||
| self._hash = hash((self.value, self.fallback)) | ||
| return self._hash | ||
| return hash(self.value) |
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Is this part actually safe? This will make Literal["foo"] and Literal[b"foo"] have same hash (I don't remember why, but we always store the literal bytes value as a string).
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There's also Literal[0] vs Literal[False], both 0 and False hash to zero IIRC
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It's fine for hashes to collide and doesn't affect correctness. You just don't want too many values to collide because then some of your constant time operations become linear.
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Only correctness requirement is that values that compare equal have the same hash
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OK, I see, could you please then add a comment explaining this pef optimization, otherwise it looks like a "typo". Otherwise this PR LG.
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According to mypy_primer, this change doesn't affect type check results on a corpus of open source code. ✅ |
If I'm doing it right, this should be 1-2% on a profile I'm looking at