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Oct 9, 2024
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DEV: replace hackers with racers on sorted sets page #749

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4 changes: 2 additions & 2 deletions content/develop/data-types/sorted-sets.md
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Expand Up @@ -57,7 +57,7 @@ As you can see [`ZADD`]({{< relref "/commands/zadd" >}}) is similar to [`SADD`](
[`ZADD`]({{< relref "/commands/zadd" >}}) is also variadic, so you are free to specify multiple score-value
pairs, even if this is not used in the example above.

With sorted sets it is trivial to return a list of hackers sorted by their
With sorted sets it is trivial to return a list of racers sorted by their
birth year because actually *they are already sorted*.

Implementation note: Sorted sets are implemented via a
Expand Down Expand Up @@ -163,7 +163,7 @@ Redis instance will reply with the same output).
The main commands to operate with lexicographical ranges are [`ZRANGEBYLEX`]({{< relref "/commands/zrangebylex" >}}),
[`ZREVRANGEBYLEX`]({{< relref "/commands/zrevrangebylex" >}}), [`ZREMRANGEBYLEX`]({{< relref "/commands/zremrangebylex" >}}) and [`ZLEXCOUNT`]({{< relref "/commands/zlexcount" >}}).

For example, let's add again our list of famous hackers, but this time
For example, let's add again our list of famous racers, but this time
using a score of zero for all the elements. We'll see that because of the sorted sets ordering rules, they are already sorted lexicographically. Using [`ZRANGEBYLEX`]({{< relref "/commands/zrangebylex" >}}) we can ask for lexicographical ranges:

{{< clients-example ss_tutorial zadd_lex >}}
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