`awk` does not support `else` statement with a single statement that does not end with `;` or `\n`.

[ghuls]

Describe the bug

awk does not support else statement with a single statement that does not end with ; or \n. \n, ; and } (from optionally a higher level) should indicate the end of a statement.

To Reproduce
Steps to reproduce the behavior:

$ target/x86_64-unknown-linux-gnu/release/awk 'BEGIN { if (1 == 1) if (2==3) print "wrongtest"; else print "test" }'
 --> 1:68
  |
1 | BEGIN { if (1 == 1) if (2==3) print "wrongtest"; else print "test" }
  |                                                                    ^---
  |
  = expected string, ere, number, func_name, truncate, append, pipe, builtin_function_call, pre_inc, pre_dec, not, unary_plus, negate, post_inc, post_dec, pow, mul, div, modulus, add, binary_sub, match_op, not_match, and, or, in_op, or lvalue

# Adding ";" or "\n" after the single statement, parses without problem.
$ target/x86_64-unknown-linux-gnu/release/awk 'BEGIN { if (1 == 1) if (2==3) print "wrongtest"; else print "test"; }'
test

$ target/x86_64-unknown-linux-gnu/release/awk 'BEGIN { if (1 == 1) if (2==3) print "wrongtest"; else print "test"
}'
test

$ gawk 'BEGIN { if (1 == 1) if (2==3) print "wrongtest"; else print "test" }'
test

$ mawk 'BEGIN { if (1 == 1) if (2==3) print "wrongtest"; else print "test" }'
test

$ goawk 'BEGIN { if (1 == 1) if (2==3) print "wrongtest"; else print "test" }'
test

$ frawk 'BEGIN { if (1 == 1) if (2==3) print "wrongtest"; else print "test" }'
test

Expected behavior

Parse else statement without ; and \n properly.

Operaing system (OS) info:

• Rocky Linux 8.9
• Version posixutils-awk 0.2.2: commit 72788d8