♻️ simplify spawn() by delegating to scope.run#1078
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We're going to end up wrapping unified APIs around most Effection functions so that they can be decorated with middleware. As such, there is no need to have separate code paths for Scope.run() and Scope.spawn() since they end up calling the same thing under the hood. This has `spawn()`` delegate to `Scope.run()` so that the apis can be unified and wrapped as one. In other words, wraping `Scope.run()` is the same as wrapping `spawn()`.
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taras
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Jan 26, 2026
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🤯 how is this is even possible?
jbolda
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Jan 26, 2026
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@taras I was actually surprised at how simple the change was. Turns out, the spawn operation is just this: let scope = yield* useScope();
return scope.run(op); |
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Isn't run also that? How are they not same? |
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They both resolve to |
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Motivation
We're going to end up wrapping unified APIs around most Effection functions so that they can be decorated with middleware. As such, there is no need to have separate code paths for Scope.run() and Scope.spawn() since they end up calling the same thing under the hood.
Approach
This has
spawn()delegate toScope.run()so that the apis can be unified and wrapped as one. In other words, wrapingScope.run()is the same as wrappingspawn().