Added more problems

algorithmic/problems/111/chk.cc

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+// chk.cc — Checker for "Distinct Pairwise XOR Set"
+// Style: modeled after the knight-path checker; prints
+// quitp(ratio, "Valid XOR set. Your=%d Best=%lld Ratio: %.8f", ...)
+// Ratio = (size of participant set) / (size of best set from ans.txt)
+
+#include "testlib.h"
+#include <bits/stdc++.h>
+using namespace std;
+
+static bool readMaybeLong(InStream& S, long long &x){
+    try { x = S.readLong(); return true; }
+    catch(...) { return false; }
+}
+static bool readMaybeInt(InStream& S, int &x){
+    try { x = S.readInt(); return true; }
+    catch(...) { return false; }
+}
+
+// Compute K = ceil(log2(n+1)) so that all XORs of numbers in [1..n] fit in [0..2^K-1]
+static int xorBitWidth(long long n){
+    unsigned long long nu = (unsigned long long)max(1LL, n);
+    int k = 64 - __builtin_clzll(nu); // ceil(log2(nu+?)), good for n>=1
+    if ((1ULL << k) <= (unsigned long long)n) ++k; // ensure 2^k > n when n is exact power-1 edge
+    return max(1, k);
+}
+
+struct ReadResult {
+    vector<int> a;
+    long long m = 0;
+};
+
+// Read "length-first" set:
+// m
+// v1 v2 ... vm
+// who = "participant" or "answer"
+static ReadResult readSetLenOnly(InStream& S, long long n, const char* who, bool allowZero){
+    ReadResult R;
+    long long m;
+    if (!readMaybeLong(S, m)){
+        if (string(who)=="participant") quitp(0.0, "Empty output (no m). Score=0.0");
+        quitf(_fail, "Answer file is empty (no m).");
+    }
+    if (m < 0 || m > n){
+        if (string(who)=="participant") quitp(0.0, "Invalid m=%lld. Score=0.0", m);
+        quitf(_fail, "Answer file: invalid m=%lld.", m);
+    }
+    if (m == 0 && !allowZero){
+        if (string(who)=="participant") quitp(0.0, "m=0 not allowed here. Score=0.0");
+        quitf(_fail, "Answer file: m=0 not allowed.");
+    }
+
+    R.m = m;
+    R.a.reserve((size_t)m);
+    vector<unsigned char> used((size_t)n + 1, 0);
+
+    for (long long i = 0; i < m; ++i){
+        int x;
+        if (!readMaybeInt(S, x)){
+            if (string(who)=="participant") quitp(0.0, "Output ended before %lld numbers. Score=0.0", m);
+            quitf(_fail, "Answer file: ended before %lld numbers.", m);
+        }
+        if (x < 1 || x > n){
+            if (string(who)=="participant") quitp(0.0, "Number out of range at pos %lld: %d (need 1..%lld). Score=0.0", i+1, x, n);
+            quitf(_fail, "Answer file: number out of range at pos %lld: %d (need 1..%lld).", i+1, x, n);
+        }
+        if (used[x]){
+            if (string(who)=="participant") quitp(0.0, "Duplicate number: %d. Score=0.0", x);
+            quitf(_fail, "Answer file: duplicate number: %d.", x);
+        }
+        used[x] = 1;
+        R.a.push_back(x);
+    }
+    // Ignore any extra tokens after m numbers.
+    return R;
+}
+
+static void checkXorDistinct(const vector<int>& a, long long n, const char* who){
+    long long m = (long long)a.size();
+    if (m <= 1) return; // vacuously distinct
+
+    int K = xorBitWidth(n);
+    long long cap = 1LL << K; // number of distinct XOR values available [0..2^K-1]
+    long long pairs = m * (m - 1) / 2;
+
+    // Quick impossibility check
+    if (pairs > cap){
+        if (string(who)=="participant")
+            quitp(0.0, "Impossible: m=%lld yields %lld pairs > %lld available XORs. Score=0.0", m, pairs, cap);
+        quitf(_fail, "Answer file: m=%lld yields %lld pairs > %lld available XORs.", m, pairs, cap);
+    }
+
+    vector<unsigned char> seen((size_t)cap, 0);
+    for (long long i = 0; i < m; ++i){
+        for (long long j = i + 1; j < m; ++j){
+            int v = a[i] ^ a[j];
+            if (seen[(size_t)v]){
+                if (string(who)=="participant")
+                    quitp(0.0, "XOR collision: a[%lld]=%d XOR a[%lld]=%d = %d already seen. Score=0.0",
+                          i+1, a[i], j+1, a[j], v);
+                quitf(_fail, "Answer file: XOR collision between indices %lld and %lld (value %d).", i+1, j+1, v);
+            }
+            seen[(size_t)v] = 1;
+        }
+    }
+}
+
+int main(int argc, char* argv[]){
+    registerTestlibCmd(argc, argv);
+    if (argc < 4) {
+        quitf(_fail, "Usage: %s in.txt out.txt ans.txt", argv[0]);
+    }
+
+    // Optional: ensure ans.txt exists and is not 0 bytes
+    {
+        ifstream f(argv[3], ios::binary);
+        if (!f) quitf(_fail, "Cannot open %s", argv[3]);
+        f.seekg(0, ios::end);
+        if (f.tellg() == 0) quitf(_fail, "ans.txt is empty (0 bytes).");
+    }
+
+    // Read input: n
+    long long n;
+    try { n = inf.readLong(1LL, 10000000LL, "n"); }
+    catch(...) { quitf(_fail, "Failed to read valid n from input."); }
+
+    // Read best (answer) and your (participant) sets
+    auto best = readSetLenOnly(ans, n, "answer", /*allowZero=*/false);
+    auto yours = readSetLenOnly(ouf, n, "participant", /*allowZero=*/true);
+
+    // Validate XOR-distinctness for both
+    checkXorDistinct(best.a, n, "answer");
+    checkXorDistinct(yours.a, n, "participant");
+
+    long long Best = best.m;
+    int Your = (int)yours.m;
+
+    double ratio = (Best == 0) ? 0.0 : (double)Your / (double)Best;
+    if (ratio < 0) ratio = 0;
+    if (ratio > 1) ratio = 1;
+
+    quitp(ratio, "Valid XOR set. Your=%d Best=%lld Ratio: %.8f", Your, Best, ratio);
+}

algorithmic/problems/111/config.yaml

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+type: default
+time: 1s
+memory: 128m
+
+checker: chk.cc
+
+subtasks:
+  - score: 100
+    n_cases: 1     # auto-picks 1.in…10.in and (logically) 1.out…10.out,
+                    # but your JudgeEngine first tries "X.ans" before "X.out".

algorithmic/problems/111/statement.txt

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+Problem: Distinct Pairwise XOR Set
+
+Time Limit: 1 second
+Memory Limit: 512 MB
+
+Description
+Given an integer n, find a subset S ⊆ {1, 2, ..., n} such that:
+1) For all pairs (a, b) with a, b ∈ S and a < b, the values (a XOR b) are all distinct (i.e., no two different unordered pairs produce the same XOR).
+2) |S| ≥ floor(sqrt(n / 2)).
+
+Input
+A single integer n (1 ≤ n ≤ 10^7).
+
+Output
+- First line: an integer m — the size of the set S.
+- Second line: m distinct integers in the range [1, n] — the elements of S, in any order.
+
+Notes
+- Any valid S is accepted. You do NOT need to maximize m; you only need m ≥ floor(sqrt(n/2)).
+- The pairwise XOR distinctness means the set {a_i XOR a_j | 1 ≤ i < j ≤ m} has size m*(m-1)/2.
+- Multiple correct outputs may exist for the same n.
+- Print out the sequence with the longest length.
+
+Sample
+Input
+49
+Output
+4
+1 2 3 4