[maths] My judge agrees with me 94% of the time. Why is that not good enough? #93
The question in one lineI hand-labelled 200 answers, ran the judge on the same 200, and they agree on 188 of them. That The numbersWhereNotebook 06, judge calibration |
Replies: 3 comments 2 replies
My first read is that 94% is fine and the notebook is being conservative. If I had a junior What is the argument that this is not enough? |
Priya has it, and κ is the arithmetic that makes it precise. κ ≈ 0.67. That is "substantial" on the Landis–Koch bands and genuinely usable — better than The reason the notebook still warns you: κ moves fast in this region. Push the class balance Practical consequence: quote κ with the base rate next to it, always. A κ without its class |
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Marking this because the thread has arrived somewhere better than the question started. Three things to take from it. 1 · Raw agreement is uninterpretable without the marginals. The full derivation, including 2 · κ ≈ 0.67 here is genuinely usable, and I want to be clear the notebook is not saying 3 · The question that matters more than the number. A judge with moderate but consistent If you are labelling more than 200, or with more than two raters, switch to Krippendorff's α — |
Marking this because the thread has arrived somewhere better than the question started.
Three things to take from it.
1 · Raw agreement is uninterpretable without the marginals. The full derivation, including
why κ has that particular denominator, is in
Cohen's κ. The short version:
1 − pₑis the agreement that wasavailable to be earned beyond chance, so κ is the share of it you actually earned.
2 · κ ≈ 0.67 here is genuinely usable, and I want to be clear the notebook is not saying
otherwise. What it warns about is treating any single κ as a stable property of the judge.
3 · The question that matters more than the number. A judge with moderate but consistent
error can still rank two sys…