[PGS[구명보트 - #91
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🍪 문제 이름
Resolve: 구명보트
🍊 문제 정의
| people | limit | return |
|---------------- -|------|--------|
| [70, 50, 80, 50] | 100 | 3 |
| [70, 80, 50] | 100 | 3 |
🍑 알고리즘 설계
풀이 과정에서 본인이 생각한 내용을 작성해 주세요.
inr배열을 deque로 새로 만들고 정렬을 했습니다. 왜냐하면 가장 최선은 작은수와 큰수의 합이기 때문에 deque의 앞과 뒤에서 숫자를 꺼내면 자연스럽게 될 수 있습니다.
while(!p_list.isEmpty()){
if(p_list.size()==1){
p_list.pollFirst();
count++;
break;
}
int small = p_list.peekFirst();
int big = p_list.peekLast();
if(small+ big > limit){
p_list.pollLast();
}else{
p_list.pollFirst();
p_list.pollLast();
}
count++;
}
🥝 최악 수행 시간 복잡도
O()🍰 특이 사항 (Optional)
참고 자료나 추가로 설명하고 싶은 내용을 작성해 주세요.