Skip to content
Open
Show file tree
Hide file tree
Changes from all commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
2 changes: 1 addition & 1 deletion 02_activities/assignments/DC_Cohort/Assignment1.md
Original file line number Diff line number Diff line change
Expand Up @@ -209,5 +209,5 @@ Consider, for example, concepts of fariness, inequality, social structures, marg


```
Your thoughts...
Databases might seem like just a technical tool for storing information, but after reading this article, I started to realize they actually reflect certain values and assumptions. For example, the system described in the article assumes that everyone fits into a traditional family structure, which is not true for many people. Because of this, some individuals were excluded or faced difficulties when the database could not recognize their situation. This made me think that databases can create unfairness, even if that is not the intention. In my everyday life, I also see similar situations, like when filling out forms that only allow limited options for gender or family background. These systems simplify people’s identities, but in doing so, they may ignore important differences and experiences. As someone new to this topic, I am beginning to understand that technology is not neutral, and the way databases are designed can shape how people are treated in society.
```
Loading
Sorry, something went wrong. Reload?
Sorry, we cannot display this file.
Sorry, this file is invalid so it cannot be displayed.
140 changes: 93 additions & 47 deletions 02_activities/assignments/DC_Cohort/assignment1.sql
Original file line number Diff line number Diff line change
Expand Up @@ -6,28 +6,28 @@
--SELECT
/* 1. Write a query that returns everything in the customer table. */
--QUERY 1




SELECT *
FROM customer
--END QUERY


/* 2. Write a query that displays all of the columns and 10 rows from the customer table,
sorted by customer_last_name, then customer_first_ name. */
--QUERY 2




SELECT*
FROM customer
ORDER BY customer_last_name, customer_first_name
LIMIT 10;
--END QUERY


--WHERE
/* 1. Write a query that returns all customer purchases of product IDs 4 and 9.
Limit to 25 rows of output. */


SELECT *
FROM customer_purchases
WHERE product_id IN (4,9)
LIMIT 25;

/*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty),
filtered by customer IDs between 8 and 10 (inclusive) using either:
Expand All @@ -36,10 +36,11 @@ filtered by customer IDs between 8 and 10 (inclusive) using either:
Limit to 25 rows of output.
*/
--QUERY 3




SELECT *
,quantity * cost_to_customer_per_qty AS price
FROM customer_purchases
WHERE customer_id BETWEEN 8 AND 10
LIMIT 25;
--END QUERY


Expand All @@ -49,47 +50,60 @@ Using the product table, write a query that outputs the product_id and product_n
columns and add a column called prod_qty_type_condensed that displays the word “unit”
if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
--QUERY 4




SELECT
product_id,
product_name,
CASE
WHEN product_qty_type = 'unit' THEN 'unit'
ELSE 'bulk'
END AS prod_qty_type_condensed
FROM product;
--END QUERY


/* 2. We want to flag all of the different types of pepper products that are sold at the market.
add a column to the previous query called pepper_flag that outputs a 1 if the product_name
contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
--QUERY 5




SELECT
product_id,
product_name,
CASE
WHEN product_qty_type = 'unit' THEN 'unit'
ELSE 'bulk'
END AS prod_qty_type_condensed,
CASE
WHEN LOWER(product_name) LIKE '%pepper%' THEN 1
ELSE 0
END AS pepper_flag
FROM product;
--END QUERY


--JOIN
/* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the
vendor_id field they both have in common, and sorts the result by market_date, then vendor_name.
Limit to 24 rows of output. */
--QUERY 6




SELECT *
FROM vendor v
INNER JOIN vendor_booth_assignments vba
ON v.vendor_id = vba.vendor_id
ORDER BY vba.market_date, v.vendor_name
LIMIT 24;
--END QUERY



/* SECTION 3 */

-- AGGREGATE
/* 1. Write a query that determines how many times each vendor has rented a booth
at the farmer’s market by counting the vendor booth assignments per vendor_id. */
--QUERY 7




SELECT
vendor_id,
COUNT(*) AS booth_count
FROM vendor_booth_assignments
GROUP BY vendor_id;
--END QUERY


Expand All @@ -99,13 +113,24 @@ of customers for them to give stickers to, sorted by last name, then first name.

HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
--QUERY 8




SELECT
c.customer_id,
c.customer_first_name,
c.customer_last_name,
SUM(cp.quantity * cp.cost_to_customer_per_qty) AS total_spent
FROM customer c
INNER JOIN customer_purchases cp
ON c.customer_id = cp.customer_id
GROUP BY
c.customer_id,
c.customer_first_name,
c.customer_last_name
HAVING SUM(cp.quantity * cp.cost_to_customer_per_qty) > 2000
ORDER BY c.customer_last_name, c.customer_first_name;
--END QUERY



--Temp Table
/* 1. Insert the original vendor table into a temp.new_vendor and then add a 10th vendor:
Thomass Superfood Store, a Fresh Focused store, owned by Thomas Rosenthal
Expand All @@ -118,10 +143,24 @@ When inserting the new vendor, you need to appropriately align the columns to be
VALUES(col1,col2,col3,col4,col5)
*/
--QUERY 9




CREATE TEMP TABLE new_vendor AS
SELECT *
FROM vendor;

INSERT INTO new_vendor (
vendor_id,
vendor_name,
vendor_type,
vendor_owner_first_name,
vendor_owner_last_name
)
VALUES (
10,
'Thomass Superfood Store',
'Fresh Focused',
'Thomas',
'Rosenthal'
);
--END QUERY


Expand All @@ -132,10 +171,12 @@ HINT: you might need to search for strfrtime modifers sqlite on the web to know
and year are!
Limit to 25 rows of output. */
--QUERY 10




SELECT
customer_id,
STRFTIME('%m', market_date) AS month,
STRFTIME('%Y', market_date) AS year
FROM customer_purchases
LIMIT 25;
--END QUERY


Expand All @@ -146,8 +187,13 @@ HINTS: you will need to AGGREGATE, GROUP BY, and filter...
but remember, STRFTIME returns a STRING for your WHERE statement...
AND be sure you remove the LIMIT from the previous query before aggregating!! */
--QUERY 11
SELECT
customer_id,
SUM(quantity * cost_to_customer_per_qty) AS total_spent
FROM customer_purchases
WHERE STRFTIME('%m', market_date) = '04'
AND STRFTIME('%Y', market_date) = '2022'
GROUP BY customer_id;
--END QUERY




--END QUERY
46 changes: 46 additions & 0 deletions 04_this_cohort/Mar26_Live code.sql
Original file line number Diff line number Diff line change
@@ -0,0 +1,46 @@
/* MODULE 2 */
/* LEFT JOIN */


/* 1. There are products that have been bought
... but are there products that have not been bought?
Use a LEFT JOIN to find out*/
SELECT DISTINCT
p.product_id
,cp.product_id as [cp.product_id]
,product_name

FROM product as p
LEFT JOIN customer_purchases as cp
ON p.product_id = cp.product_id

/* 2. Directions of LEFT JOINs matter ...*/

FROM customer_purchases as cp
LEFT JOIN product as p
ON p.product_id = cp.product_id;


/* 3. As do which values you filter on ... */
SELECT DISTINCT
p.product_id
,cp.product_id



/* 4. Without using a RIGHT JOIN, make this query return the RIGHT JOIN result set
...**Hint, flip the order of the joins** ...

SELECT *

FROM product_category AS pc
LEFT JOIN product AS p
ON pc.product_category_id = p.product_category_id
ORDER by pc.product_category_id

...Note how the row count changed from 24 to 23
*/



--------------------------------------------------------------------------------------------------------------------------------------------
Loading