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3 changes: 2 additions & 1 deletion 02_activities/assignments/Assignment2.md
Original file line number Diff line number Diff line change
Expand Up @@ -54,7 +54,8 @@ The store wants to keep customer addresses. Propose two architectures for the CU
**HINT:** search type 1 vs type 2 slowly changing dimensions.

```
Your answer...
Type 1: Overwrites the address, retaining only the latest value (no historical data).
Type 2: Retains a historical record of all address changes, tracking them with effective dates.
```

***
Expand Down
78 changes: 69 additions & 9 deletions 02_activities/assignments/assignment1.sql
Original file line number Diff line number Diff line change
Expand Up @@ -4,21 +4,25 @@

--SELECT
/* 1. Write a query that returns everything in the customer table. */
select * from customer;



/* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table,
sorted by customer_last_name, then customer_first_ name. */

select * from customer
order by customer_last_name, customer_first_name limit 10;


--WHERE
/* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
-- option 1

select * from customer_purchases
where product_id = 4 or product_id =9;

-- option 2

select * from customer_purchases
where product_id in (4,9);


/*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty),
Expand All @@ -27,9 +31,15 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either:
2. one condition using BETWEEN
*/
-- option 1
select *, (quantity * cost_to_customer_per_qty) as price
from customer_purchases
where vendor_id between 8 and 10;


-- option 2
select *, (quantity * cost_to_customer_per_qty) as price
from customer_purchases
where vendor_id >= 8 and vendor_id <= 10;



Expand All @@ -38,27 +48,46 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either:
Using the product table, write a query that outputs the product_id and product_name
columns and add a column called prod_qty_type_condensed that displays the word “unit”
if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */

select product_id, product_name,
Case
When product_qty_type = 'unit' Then 'unit'
Else 'bulk'
End as prod_qty_type_condensed from product;


/* 2. We want to flag all of the different types of pepper products that are sold at the market.
add a column to the previous query called pepper_flag that outputs a 1 if the product_name
contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */

select product_id, product_name,
Case
When product_qty_type = 'unit' Then 'unit'
Else 'bulk'
End as prod_qty_type_condensed,
Case
When product_name like '%pepper%' Then 1
Else 0
End as 'pepper_flag' from product;


--JOIN
/* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the
vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */


select *
from vendor v join vendor_booth_assignments vba
on v.vendor_id = vba.vendor_id
order by v.vendor_name, vba.market_date;


/* SECTION 3 */

-- AGGREGATE
/* 1. Write a query that determines how many times each vendor has rented a booth
at the farmer’s market by counting the vendor booth assignments per vendor_id. */
select v.vendor_name, v.vendor_id, count(vba.booth_number) as number_of_booths
from vendor v join vendor_booth_assignments vba
on v.vendor_id = vba.vendor_id
group by v.vendor_id
order by v.vendor_name, vba.market_date;



Expand All @@ -67,7 +96,18 @@ sticker to everyone who has ever spent more than $2000 at the market. Write a qu
of customers for them to give stickers to, sorted by last name, then first name.

HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */

with cte as (
select c.customer_id, c.customer_first_name, c.customer_last_name,
(cp.quantity * cp.cost_to_customer_per_qty) as price
from customer c join customer_purchases cp
on c.customer_id = cp.customer_id
) select customer_id,
customer_first_name, customer_last_name,
sum(price) as total_money_spent
from cte
group by customer_id
having sum(price) > 2000
order by customer_last_name, customer_first_name;


--Temp Table
Expand All @@ -81,15 +121,23 @@ When inserting the new vendor, you need to appropriately align the columns to be
-> To insert the new row use VALUES, specifying the value you want for each column:
VALUES(col1,col2,col3,col4,col5)
*/
create temp table new_vendor as
select * from vendor;

select * from new_vendor;

insert into new_vendor values(10, 'Thomass Superfood Store', 'Fresh Focused', 'Thomas', 'Rosenthal');


-- Date
/*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.

HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month
and year are! */

select customer_id,
strfrtime('%m', market_date) as month,
strfrtime('%Y', market_date) as year
from customer_purchases


/* 2. Using the previous query as a base, determine how much money each customer spent in April 2022.
Expand All @@ -98,3 +146,15 @@ Remember that money spent is quantity*cost_to_customer_per_qty.
HINTS: you will need to AGGREGATE, GROUP BY, and filter...
but remember, STRFTIME returns a STRING for your WHERE statement!! */

with cte as (
select *,
(quantity * cost_to_customer_per_qty) as price,
strftime('%m', market_date) as month,
strftime('%Y', market_date) as year
from customer_purchases
)
select customer_id, month, year,
sum(price) as total_april_spent
from cte
where month = '04' and year = '2022'
group by customer_id
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