display those employees who contain a letter z to their first name and also display their last name, city.
select t1.first_name, t1.last_name, t3.city from employees as t1 join departments as t2 on t1.department_id = t2.department_id join locations as t3 on t2.location_id = t3.location_id where t1.first_name like '%z%'