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Problem in High Water Mark option in ZMQ communication #1241

Description

@agn-7

I have a problem in High Water Mark option in ZMQ communication:

According to the ZeroMQ documentation, a pub socket is supposed to drop messages once the number of queued messages reaches the high-water mark.

This doesn't seem to work in the following example (and yes I do set the hwm before bind/connect):

import time
import pickle
from threading import Thread
import zmq

ctx = zmq.Context()

def pub_thread():
    pub = ctx.socket(zmq.PUB)
    pub.set_hwm(2)
    pub.bind('tcp://*:5555')

    i = 0
    while True:
        # Send message every 100ms
        time.sleep(0.1)
        pub.send_string("test", zmq.SNDMORE)
        pub.send_pyobj(i)
        i += 1

def sub_thread():
    sub = ctx.socket(zmq.SUB)
    sub.subscribe("test")
    sub.connect('tcp://localhost:5555')
    while True:
        # Receive messages only every second
        time.sleep(1)
        msg = sub.recv_multipart()
        print("Sub: %d" % pickle.loads(msg[1]))

t_pub = Thread(target=pub_thread)
t_sub = Thread(target=sub_thread)
t_pub.start()
t_sub.start()

while True:
    pass

I'm sending messages on pub 10 times faster than reading them on the sub socket, hwm is set to 2. I would expect to only receive about every 10th message. Instead, I see the following output:

Sub: 0
Sub: 1
Sub: 2
Sub: 3
Sub: 4
Sub: 5
Sub: 6
Sub: 7
Sub: 8
Sub: 9
Sub: 10
Sub: 11
Sub: 12
Sub: 13
Sub: 14
...

So I see all messages arriving, thus they are held in some queue until I read them. Same holds true when adding a hwm=2 on the sub socket as well before connect.

What am I doing wrong or am I misunderstanding hwm?

I use pyzmq version 17.1.2


Also I tried with the following code, but result was the same:

import time
import pickle
import zmq
from threading import Thread

ctx = zmq.Context()

def pub_thread():
    pub = ctx.socket(zmq.PUB)
    pub.setsockopt(zmq.SNDHWM, 2)  # This line was changed.
    pub.bind('tcp://*:5555')

    i = 0
    while True:
        time.sleep(0.1)
        pub.send_string("test", zmq.SNDMORE)
        pub.send_pyobj(i)
        i += 1

def sub_thread():
    sub = ctx.socket(zmq.SUB)
    sub.setsockopt(zmq.SUBSCRIBER, b'')
    sub.setsockopt(zmq.RCVHWM, 2)  # This line added.
    # sub.setsockopt(zmq.CONFLATE, 1)  # Last msg only (another option).
    sub.connect('tcp://localhost:5555')
    while True:
        time.sleep(1)
        msg = sub.recv_multipart()
        print("Sub: %d" % pickle.loads(msg[1]))

t_pub = Thread(target=pub_thread)
t_pub.start()
sub_thread()  # Start with main thread.

These posts (POST1, POST2, POST3) are relevant to this issue in the Stack Overflow.


Thanks in advance,

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