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问一块蛋糕切N刀最多能切成几块。
相当于N条直线最多能把平面划分成几块。 N = 0时,ans = 1。 N = 1, ans = 2 N = 2, ans = 4 N = 3, ans = 7 N = 4, ans = 11
每加第x条直线,都应该和x-1条直线相交,这样才能得到最多的平面数。 递推得知,答案就是数列{1, 2, 3, 4, 5...}的前N项和 + 1(没有直线时平面数为1)。