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n个人坐在圆桌上,每次只能调换相邻两个人的位置,问需要调换多少次才能使所有人坐的方向和原来相反。 最快的方法,就是把所有人分成 1n/2 和 n/2+1n 两组,然后看成直线在内部调换。 所以答案是sigma(n / 2 - 1) + sigma((n - 1) / 2 - 1)