Exponential & logarithmic equations

[WhiteBlackGoose]

So that a ^ f(x) + b ^ g(x) + ... = 0 could be solved. And, likewise, a logarithmic one

[WhiteBlackGoose]

@MomoDeve wanna be an assignee for this one?

[MomoDeve]

1. a ^ f(x) + b ^ g(x) + ... + t = 0 can be solved only if all functions are linear or can be converted to linear by substitution: for example, 2^(x^2 + 1) + 2^(2*x^2 - 1) + 1 = 0 can be solved, but2^(x + 1) + 2^(2*x^2 - 1) + 1 = 0 cannot.
2. where are no exponential parsers. I have an idea how to solve such equations, but it requires a lot of dirty work just to determine if an equation is solvable and which substitution to choose