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152. Maximum Product Subarray
Jacky Zhang edited this page Nov 6, 2016
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2 revisions
Find the contiguous subarray within an array (containing at least one number) which has the largest product.
For example, given the array [2,3,-2,4], the contiguous subarray [2,3] has the largest product = 6.
解题思路为Dynamic Programming。
令f(i)表示以nums[i]结尾的largest product subarray, g(i)表示以nums[i]结尾的smallest product subarray。
f(i) = max(nums[i], f(i-1)*nums[i], g(i-1)*nums[i])
g(i) = min(nums[i], f(i-1)*nums[i], g(i-1)*nums[i])
public class Solution {
public int maxProduct(int[] nums) {
if(nums == null || nums.length == 0) return 0;
int max = nums[0], min = nums[0], res = nums[0];
for(int i = 1; i < nums.length; i++) {
int preMax = max, preMin = min;
max = Math.max(Math.max(nums[i], preMax * nums[i]), preMin * nums[i]);
min = Math.min(Math.min(nums[i], preMax * nums[i]), preMin * nums[i]);
res = Math.max(res, max);
}
return res;
}
}