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day 3 challenge #782

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Merged
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Dec 12, 2020
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day 3 challenge #782

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4ff39cf
day 3 challenge pomodoro timer
lauranutanix Dec 7, 2020
14896a8
clean up
lauranutanix Dec 7, 2020
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46 changes: 46 additions & 0 deletions 52/lauramariel/pomodoro.py
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import time
from datetime import datetime
from datetime import timedelta
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@bbelderbos bbelderbos Dec 12, 2020

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Can do in one import: from datetime import datetime, timedelta


def timer(timer_type):
if timer_type == "pomodoro":
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@bbelderbos bbelderbos Dec 12, 2020

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the only difference here are the number of minutes, so you could turn this into a dictionary: timer_times = {'pomodoro': 25, 'short_break': 5, 'long_break': 10}, then you don't have to repeat endtime = datetime.now() + timedelta(minutes=<int>) 3 times

endtime = datetime.now() + timedelta(minutes=25)
elif timer_type == "short_break":
endtime = datetime.now() + timedelta(minutes=5)
elif timer_type == "long_break":
endtime = datetime.now() + timedelta(minutes=10)

while (datetime.now().replace(microsecond=0) != endtime.replace(microsecond=0)):
timeleft = endtime - datetime.now()
timeleft = str(timeleft).split(".")[0]
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@bbelderbos bbelderbos Dec 12, 2020

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Or:

>>> timeleft
datetime.timedelta(seconds=9, microseconds=687388)
>>> timeleft.seconds
9

print(f"{timeleft}", end='\r')
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@bbelderbos bbelderbos Dec 12, 2020

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Is \r something you had to do for Windows?

time.sleep(1)

print(f"{timer_type} done!")
return True

def main():
pomodoro_count = 0
while True:
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@bbelderbos bbelderbos Dec 12, 2020

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Is there anything that would break out of this loop?

intervals = ["pomodoro", "break"]

for timer_type in intervals:

if timer_type == "pomodoro":
pomodoro_count += 1
print(f"It's work time! Pomodoro #{pomodoro_count}")

if timer_type == "break":
# determine whether it's a short or long break
if pomodoro_count < 4:
# it's a short break
timer_type = "short_break"
else:
timer_type = "long_break"
pomodoro_count = 0
print(f"Starting {timer_type}!")

timer(timer_type=timer_type)

if __name__ == "__main__":
main()