lambda

In C++, a lambda expression is syntactic sugar for a functor. Under the hood, the compiler transforms every lambda into an anonymous class that overloads the call operator operator()

f:_book_development\c++\2010-2019\2016-Эффективный и современный С++11 C++14.pdf f:_book_development\c++\2010-2019\2014-Exploring C++ 11, 2nd ed-Lischner.pdf https://www.youtube.com/watch?v=GPBY8KNGbhc https://www.youtube.com/watch?v=CFOIHo5aNTo